Question

Find the equation of the line that passes through the points (12,21) and (46,33). V.35r-162

Answer 1

the answer is Y=(6/17)X + (285/17)

Explanation:

1. Identify the X and Y coordinate of each point.

for example, the first point could be (12,21), therefore X1 = 12 and Y1 = 21 and the second point is then (46,33), therefore X2 = 46 and Y2 = 33

2. to find the equation of the line it is necessary to find the slope.

knowing that the equiation of the slope is M = Y2-Y1/X2-X1 we replace

`m=(33-21)/(46-12)=(12)/(34)` and then we simplify the result to
`(12)/(34)`

3. Using the Point-slope equation which is Y-Y1=M(X-X1) we replace

`Y-33=(6)/(17)(X-46)`

`Y=(6)/(17)X-(276)/(17)+33`

`Y=(6)/(17)X+(285)/(17)`