Answer:
0.0478 T
Step-by-step explanation:
L = 2 cm = 0.02 m, N = 400, i = 1.9 A
The magnetic field intensity due to a current carrying solenoid is given by
B = \mu _{0}ni
Where, n be the number of turns per unit length
n = N / L = 400 / 0.02 = 20,000
B = 4\pi \times 10^{-7}\times 20000\times 1.9
B = 0.0478 T