Question

A group of physics students hypothesize that for an experiment they are performing, the speed of an object sliding down an inclined plane will be given by the expression v=2gd(sin(θ)−μkcos(θ))−−−−−−−−−−−−−−−−−−√. For their experiment, d=0.725meter, θ=45.0∘, μk=0.120, and g=9.80meter/second2. Use your calculator to obtain the value that their hypothesis predicts for v.

Answer 1

`v = 2.97 m/s`

Step-by-step explanation:

As we know that the velocity expression for the given experiment is

`v = √(2gd(sin\theta - \mu_kcos\theta))`

now we know that

d = 0.725 m

`\theta = 45 ^o`

`\mu_k = 0.120`

`g = 9.80`

now we have

`v = √(2(9.80)(0.725)(sin45 - 0.120cos45))`

`v = 2.97 m/s`

Answer 2

v = 2.974

Step-by-step explanation:

Perhaps the formula should be

v = √(2*g*d (sin(θ) - uk*cos(θ) ) This is a bit easier to read.

v = √(2* 9.80*0.725(0.707 - 0.12*0.707) ) Substitute values. Find 2*g*d

v = √14.21 * (0.707 - 0.0849) Figure out Sin(θ) - uk cos(θ)

v = √14.21 * (0.6222)

v = √8.8422 Take the square root of the value

v = 2.974