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Solve and graph the absolute value inequality: |2x + 4| > 8. number line with open circles on negative 6 and 2, shading in between. number line with closed circles on negative 6 and 2, shading going in the opposite directions. number line with open circles on negative 6 and 2, shading going in the opposite directions. number line with open circles on negative 2 and 2, shading going in the opposite directions.

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Answer:

Part 1) The solution of the absolute value is (-∞,-6)∪ (2,∞)

Number line with open circles on negative 6 and 2, shading going in the opposite directions

Part 2) The graph in the attached figure

Explanation:

we have


\left|2x+4\right|>8

we know that

The absolute value has two solutions

step 1

Find the positive case


+(2x+4)>8


2x>8-4


2x>4


x>2

The solution is the interval ----> (2,∞)

All real numbers greater than 2

step 2

Find the negative case


-(2x+4)>8

Multiply by -1 both sides


(2x+4)<-8


2x<-8-4


2x<-12


x< -6

The solution is the interval ----> (-∞,-6)

All real numbers less than -6

therefore

The solution of the absolute value is

(-∞,-6)∪ (2,∞)

Number line with open circles on negative 6 and 2, shading going in the opposite directions

step 3

using a graphing tool

see the attached figure

Solve and graph the absolute value inequality: |2x + 4| > 8. number line with open-example-1
User Andrelrms
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