Question

Simplify each expression. e^(ln 1) = e^(ln 5x) =

Answer 1

Answer: it’s 1 and 5x on edg

Explanation:

Answer 2

`\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^(log_a x)=x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ e^(\ln(1))=e^(\ln(5x))\implies e^(\log_e(1))=e^(\log_e(5x))\implies 1=5x\implies \cfrac{1}{5}=x`