Question

A farm stand sells apples, a for $4 a bucket and peaches, p, for $6 a bucket

The stand earned $192 revenue last month. The stand sold twice as many
peach buckets as apple buckets. Which system of equations represents this
scenario?

A. 4a+6p = 192; p = a+2
B. 6a+4p = 192; p = 2a
C. 4a+6p = 192; p =2a
D. 6a+4p = 192; p = a+2​

Answer 1

C. 4a+6p = 192; p =2a

Explanation:

Here, a represents the number of apple buckets,

p represents the number of peach buckets,

Since, apples were sold for $4 a bucket and peaches were sold for $6 a bucket,

Thus, the total revenue = 4a + 6p

Given, total revenue = $192,

⇒ 4a + 6p = 192,

Now, twice as many peach buckets as apple buckets were sold.

⇒ p = 2a

Hence, the system of equations represents this scenario,

4a+6p = 192; p =2a,

Option 'C' is correct.

Answer 2

C is the correct option.

Explanation:

According to the statement:

A farm stand sells apples, a for $4 a bucket and peaches, p, for $6 a bucket

The stand earned $192 revenue last month:.

Therefore the equation is:

4a+6p= $192

The stand sold twice as many peach buckets as apple buckets:

Thus p=2a.

4a+6p=$192 --------equation 1

p=2a -----equation 2

Hence the correct option is C....