Question

Solving Quadratic Equations posttest

A.
B.
C.
D.

Answer 1

D.
`x = 3 \pm √(10)`

Explanation:

`x^2 - 6x - 1 = 0`

`x = (-b \pm √(b^2 - 4ac))/(2a)`

a = 1; b = -6; c = -1

`x = (-(-6) \pm √((-6)^2 - 4(1)(-1)))/(2(1))`

`x = (6 \pm √(36 + 4))/(2)`

`x = (6 \pm √(40))/(2)`

`x = (6 \pm √(4 * 10))/(2)`

`x = (6 \pm 2 √(10))/(2)`

`x = 3 \pm √(10)`