96.7k views
5 votes
6х + 4ув 32
-6х + 4 y = 8​

User Jnancheta
by
8.2k points

1 Answer

4 votes

Answer:

The Solution set is (x,y){(2,5)}

Explanation:

The given equation is:

6x+4y=32

-6x+4y=8

We will use the elimination method:

By this method we will eliminate the variable x.

6x+4y=32

-6x+4y=8

________

8y=40

Divide both the sides by 8

8y/8=40/8

y=5

Now substitute the value of y in equation 2:

-6x+4y=8

-6x+4(5)=8

-6x+20=8

Move the constant value to the R.H.S

-6x=8-20

-6x= -12

Divide both the terms by -6

-6x/-6 = -12/-6

x= 2

The Solution set is (x,y){(2,5)}....

User Albie
by
7.7k points

Related questions

asked Nov 7, 2024 181k views
Haseeb Mohamed asked Nov 7, 2024
by Haseeb Mohamed
8.6k points
1 answer
4 votes
181k views
asked Oct 10, 2024 168k views
Sepidol asked Oct 10, 2024
by Sepidol
7.8k points
1 answer
4 votes
168k views
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.