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Write the first four terms of the sequence.

ak = 2 + 3k, for all integers k ≥ 1

User Al Grant
by
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1 Answer

3 votes

Answer:

The first four terms of the sequence are:


a_(1) = 5


a_(2) = 8


a_(3) = 11


a_(4) = 14

Explanation:

To find a term in the sequence, we have to replace the sequence for a concrete value of k.

Since the sequence is defined for all integers k ≥ 1, then the first value is k = 1. Then, the first four terms are 1, 2, 3 and 4.

Let's evaluate the sequence with these values...


a_(1) = 2 + 3(1) = 2 + 3 = 5 => a_(1) = 5


a_(2) = 2 + 3(2) = 2 + 6 = 8 => a_(2) = 8


a_(3) = 2 + 3(3) = 2 + 9 = 11 => a_(3) = 11


a_(4) = 2 + 3(4) = 2 + 12 = 14 => a_(4) = 14

User Keele
by
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