Let x be the unknown number. 5 times that number means 5x. If we subtract 189 from this number, we get 5x-189.
Also, half the original number is x/2.
The two operations output the same result, so we have the following equation:
![5x-189 = (x)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jbdupmgi7tg6woi492l15k1ikb1tizkra2.png)
Subtract x/2 from both sides and add 189 to both sides to get
![5x-(x)/(2)=189 \iff (9x)/(2)=189](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ju51bpbw1ueb0k8ryqa0lgub4tmp4jfq65.png)
Multiply both sides by 2 to get
![9x=378](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gvlcayi7nlieyu357wg5182zxzu8kh2e55.png)
Finally, divide both sides by 9:
![x = (378)/(9)=42](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n61gvk9m86jnunj5za0hn879i5rbodpjef.png)