Question

What does this equation, 2 C(s) + O 2(g) ® 2 CO(g), tell us?

A) the number of atoms of each kind in reactants and products is the same
B) carbon monoxide (CO) is a product
C) two atoms of carbon undergo reaction
D) all of these

Answer 1

D) All of these

Step-by-step explanation:

`2 C(s) + O_2 (g) > 2 CO(g)`

Reactant side (Left side) Element Product side (Right side)

2 C 2

2 O 2

Balanced!!!

Balancing is making the number of atoms of each element same on both the sides (reactant and product side).

To find the number of atoms of each element we multiply coefficient × subscript

For example
`5 Ca_1 Cl_2` contains

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms

If there is a bracket in the chemical formula

For example
`3Ca_3 (P_1 O_4 )_2` we multiply coefficient × subscript × number outside the bracket.......... to find the number of atoms (Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms

3 × 1 × 2 = 6, P atoms

3 × 4 × 2 = 24, O atoms are present.

Answer 2

D. All of these.

Step-by-step explanation:

For an equation to be balanced the number of atoms of each kind in the reactants and the products should be the same.

Then from this equation, CO is a product.

Last, two carbon atoms undergo reaction with the oxygen molecule for complete reaction to occur. Each atom combines with one oxygen atom.