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Solve (x + 2<5) n (x-7>-6).
{x11 {x1x < 3 or x> 1)
{all real numbers)

1 Answer

2 votes

For this case we must solve
x + 2 <5intersected with
x-7> -6

So, we have:


x + 2 <5\\x <5-2\\x <3

The solutions are given by all strict minor numbers to 3.


x-7> -6\\x> -6 + 7\\x> 1

The solutions are given by all the major strict numbers to 1.

If we intersect the solutions of both equations we have
x <3
x> 1.

The intersection is given by
1 <x <3

Answer:

The solution interval is (1,3)

User ViktorZ
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