Answer: -194 mph
Step-by-step explanation:
Taking into account the Sun as the center (origin, point zero) of the reference system, the velocity of the spacecraft relative to the Sun
is:
Note it is positive because the spacecraft is moving away from the Sun
Taking into account the spacecraft as the center of another reference system, the velocity of the asteroid relative to the spacecraft
is:
Note it is negative because the asteroid is moving towards the spacracft.
Now, the velocity of the asteroid relative to the Sun
is:
![V_(A-S)=V_(A-R)-V_(R-S)](https://img.qammunity.org/2020/formulas/physics/middle-school/pkfnlvuner5e7hjfyts2uvfvmbirob9o7q.png)
![V_(A-S)=-68mph-126mph](https://img.qammunity.org/2020/formulas/physics/middle-school/owwlixpg1yujmbpg8t05eit32ilgaz246x.png)
Finally:
This is the velocity of the asteroid relative to the Sun and its negative sign indicates it is moving towards the Sun.