What is the product x^2-16/2x+8*x^3-2x^2+x/x^2+3x-4

Question

asked Jul 17, 2020 139k views

2 Answers

Martin Verjans · Answer 1 · 2020-07-23T05:49:02+0000

Answer: First Option

(x(x-4)(x-1))/(2(x+4))

Explanation:

We have the following expression

(x^2-16)/(2x+8)*(x^3-2x^2+x)/(x^2+3x-4)

First factorize the denominators:

(x^2-16)/(2(x+4))*(x^3-2x^2+x)/((x+4)(x-1))

Now we factor the numerators

((x-4)(x+4))/(2(x+4))*(x(x^2-2x+1))/((x+4)(x-1))

((x-4)(x+4))/(2(x+4))*(x(x-1)^2)/((x+4)(x-1))

now we simplify the expression

((x-4))/(2)*(x(x-1))/((x+4))

(x(x-4)(x-1))/(2(x+4))

The answer is the first option