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If a ball is thrown vertically upward from the roof of a 32 foot tall building with a velocity of 48 ft/sec, its height in feet after T seconds is ______.

User Ennael
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1 Answer

5 votes

Answer:

The ball's maxium height after 1.49 seconds will be 103.52 feet.

Step-by-step explanation:

Vi= 48 ft/sec

hi= 32 ft

hf= ?

time of maxium height :

t= Vi/g t= 48 ft/sec / 32.17 ft/secĀ²

t= 1.49 sec

maxium height:

hf= hi + Vi * t

hf= 32ft + 48 ft/sec * 1.49 sec

hf= 103.52 ft

User Dummmy
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