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If a line crosses the y-axis at (0, 1) and has a slope of 4/5, what is the equation of the line?

2 Answers

5 votes

Answer:

5y - 4x = 5. This gives you your points with a slope of 4/5

3 votes

Answer:


y=(4)/(5)x+1

Explanation:

We are given the slope, and the y-intercept. So we can use the slope-intercept equation. Which is as follows:


y=mx+b

where
m is the slope and
b is the y-intercept (the value of
y when
x=0).

The information that we have is that the slope of the line is:


m=(4)/(5)

and that the line crosses the y-axis at (0, 1).

From this point we can find the y-intercept
b, because b is the value of
y when
x=0.

And since the line passes through (0, 1) when
x = 0,
y =1. Thus, the y-intercept is:


b=1

substituting the values of the slope and the y-intercept into the equation:


y=mx+b\\y=(4)/(5)x+1

the answer is:
y=(4)/(5)x+1

User DGarvanski
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