Question

Find all values of x that are NOT in the domain of h.

If there is more than one value, separate them with commas.

h(x) = x + 1 / x^2 + 2x + 1

Answer 1

if x=-1 then its is NOT in the domain of h.

Explanation:

Domain is the set of values for which the function is defined.

we are given the function

h(x) = x + 1 / x^2 + 2x + 1

h(x) = x+1 /x^2+x+x+1

h(x) = x+1/x(x+1)+1(x+1)

h(x) = x+1/(x+1)(x+1)

h(x) = x+1/(x+1)^2

So, the function h(x) is defined when x ≠ -1

Its is not defined when x=-1

So, if x=-1 then its is NOT in the domain of h.

Answer 2

Answer:
`x=-1`

Explanation:

Given the function h(x):

`h(x)=(x+1)/( x^2 + 2x + 1)`

The values that are not in the domain of this function are those values that make the denominator equal to zero.

Then, to find them, you can make the denominator equal to zero and solve for "x":

`x^2 + 2x + 1=0\\\\(x+1)(x+1)=0\\\\(x+1)^2=0\\\\x=-1`