Question

27a⁰c³ for a =⅔, c = -⅓

need answer and if you could explain how to solve problem that would be much appreciated.​

Answer 1

- 1

Explanation:

Using the rules of exponents

`a^(0)` = 1

`(a^n)^(m)` =
`a^(nm)`

Given

27
`a^(0)`
`(-(1)/(3)) ^(3)`

Note
`a^(0)` = 1 for any value of a, thus

= 27 × 1 × -
`(1)/(3^(3) )`

= 27 × 1 × -
`(1)/(27)` ← cancel the 27 on numerator/ denominator

= 1 × - 1

= - 1