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Jonathan must determine the solutions of the quadratic equation 0=4x^2+3x+8 which of the following is a solution to the equation.

Jonathan must determine the solutions of the quadratic equation 0=4x^2+3x+8 which-example-1

1 Answer

2 votes

Answer:

option A

Explanation:

Using quadratic formula:


x=\frac{-b+-\sqrt{b^(2)-4*a*c} }{2*a}

We will have 2 solutions.

0=4x^2+3x+8 a=4 b=3 c=8


x_(1)=\frac{-3+\sqrt{3^(2)-4*4*8} }{2*4}\\\\x_(2)=\frac{-3-\sqrt{3^(2)-4*4*8} }{2*4}

We have:


x_(1)=(-3+√(9-128) )/(8)\\\\x_(2)=(-3-√(9-128) )/(8)\\\\

So


x_(1)=(-3+√(-119) )/(8)\\\\x_(2)=(-3-√(-119) )/(8)\\

The solutions are not real numbers.

We know:


i=√(-1)

We can write:


x_(1)=(-3+i√(119) )/(8)\\\\x_(2)=(-3-i√(119) )/(8)\\

so the option is A:


x_(2)=(-3-i√(119) )/(8)

User Jhonatan Sandoval
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