Question

What is the midpoint of CD?

5
4
-3
-2
-1, 1
1
2
3
4
5 x
D(4,-1)
C(-3,-4)

Answer 1

`\large\boxed{M_(CD)\left((1)/(2),\ -(5)/(2)\right)}`

Explanation:

The formula of a midpoint of a segment AB with endpoints at A(x₁, y₁) and B(x₂, y₂):

`M_(AB)\left((x_1+x_2)/(2),\ (y_1+y_2)/(2)\right)`

We have the points C(-3, -4) and D(4, -1).

Substitute:

`M_(CD)(x,\ y)\\\\x=(-3+4)/(2)=(1)/(2)\\\\y=(-4+(-1))/(2)=(-5)/(2)=-(5)/(2)`