Question

Consider the following reversible reaction.

CO(g) + 2H2(g)
CH3OH(g)

What is the equilibrium constant expression for the given system?

A.Keg = [CO][H2]2
[CH3OH)
B.Keg = (СН3ОН)(CO)(H2)2
C.Keg=
[CO][H2]
[CH3OH]
D.Keg= [Ch3OH] [CO][H2]

Answer 1

Step-by-step explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. It is expressed as
`K_(eq)`

`CO(g)+2H_2(g)\rightarrow CH_3OH(g)`

The equilibrium constant in terms of concentration is written as :

Thus the correct answer choice is B.

Answer 2

Step-by-step explanation:

For any system in equilibrium, the molar concentration of all the species on the reactant side are related to those on the product side by a constant known as the equilibrium constant
`K_(eq)`.

For a given reaction:

aA + bB ⇄ cC

`K_(eq)` =
`([C]^(c) )/([A]^(a) [B]^(b) )`

The reaction equation is given as:

`CO_(g)` + 2H₂
`_(g)` ⇆CH₃OH
`_(g)`

Note: All the species are in gaseous phase.

`K_(eq)` =
`([CH_(3)OH ])/([CO] [H_(2)] )`