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A truck moving at 36 m/s passes a police car moving at 45 m/s in the opposite direction. If the frequency of the siren is 500 Hz relative to the police car, what is the change in frequency (in Hz) heard by an observer in the truck as the two vehicles pass each other?

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Answer:

The change in frequency hearded by an observer in the truck is f'= 636.36 Hz.

Step-by-step explanation:

Vo= 36 m/s

Vf= 45 m/s

V= 342 m/s

f= 500 Hz

f'= f * ((V- (-Vo)) / (V - Vf)

f'= 636.36 Hz

User Alex Baulch
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