Question

A retail shop accepts only cash or checks suppose that 45% of its customers carry cash 44% carry checks and 31% carry both cash and checks what is the probability that a randomly chosen customer at the top of the shop is carrying cash or checks are both

Answer 1

Explanation:

The number of customers carrying cash=45% = 0.45

The number of customers carrying checks= 44% =0.44

The number of customers carrying both = 31% = 0.31

So,

To find the probability we will write the expression:

cash+checks-cash or checks(both)=cash and checks

0.45+0.44-both=0.31

0.45+0.44-0.31=both

0.58=both....