55.1k views
1 vote
Find an equation for the line that passes through the points (-6, -1) and (4, 5)

User Bowsie
by
5.2k points

2 Answers

3 votes

Answer:

y=3/5x+13/5

Explanation:

Finding the slope:

m=6/10

m=3/5

The y intercept is 13/5

Thus, the equation is y=3/5x+13/5

User Ryan Arneson
by
5.2k points
7 votes

Answer:

Equation of the given line is, y = (3/5)x +13/5

Explanation:

Points to remember

Equation of the line passing through the poits (x1, y1) and (x2, y2) and slope m is given by

(y - y1)/(x - x1) = m where slope m = (y2 - y1)/(x2 - x1)

To find the slope of line

Here (x1, y1) = (-6, -1) and (x2, y2) = (4, 5)

Slope = (y2 - y1)/(x2 - x1)

= (5 - -1)/(4 - -6)

= 6/10 = 3/5

To find the equation

(y - y1)/(x - x1) = m

(y - -1)/(x - -6) = 3/5

(y + 1)/(x + 6) = 3/5

5(y + 1) = 3(x + 6)

5y + 5 = 3x + 18

5y = 3x + 13

y = (3/5)x +13/5

User Zhang TianYu
by
4.7k points
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