Question

PLEASE HELP WITH THIS ONE AS WELL! I’m struggling with Transcendental Functions!

Answer 1

`h(x)=20e^(kx)`

a. If
`h(1)=20`, then
`20=20e^k\implies e^k=1\implies k=0`.

b. If
`h(1)=40`, then
`40=20e^k\implies e^k=2\implies k=\ln2`, so that
`2k+1=2\ln2+1`.

c. If
`h(1)=10`, then
`10=20e^k\implies e^k=\frac12\implies k=-\ln2`, so that
`k-3=-\ln2-3`.