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Please help me. I am so stuck.


Please help me. I am so stuck. ​-example-1
User Jon Kyte
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1 Answer

1 vote

Answer:

Converges to -25.

Explanation:


\sum_(k=1)^(\infty) -5 \cdot ((4)/(5))^(k-1) converges since
r=(4)/(5)<1.

The sum is given by
(a_1)/(1-r) where
a_1 is -5.


(-5)/(1-(4)/(5))=(-5)/((1)/(5))=-5(5)=-25.

User Jolyonruss
by
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