Answer:
![\boxed{\text{D. 962 K}}](https://img.qammunity.org/2020/formulas/chemistry/middle-school/wtsn9384nuimxbqt7tam1oxzwgfmnvw8zw.png)
Step-by-step explanation:
The volume and number of moles are constant, so we can use Gay-Lussac’s Law:
At constant volume, the pressure exerted by a gas is directly proportional to its temperature.
![(p_(1))/(T_(1)) = (p_(2))/(T_(2))](https://img.qammunity.org/2020/formulas/chemistry/middle-school/g73i995pvlhsnn4s26rdwf7gie43y1gkpa.png)
Data:
p₁ = 50 KPa; T₁ = 170 K
p₂ = 283 KPa; T₂ = ?
Calculations:
![\begin{array}{rcl}(50)/(170) & = & (283)/(T_(2))\\\\0.294 & = & (283)/(T_(2))\\\\0.294T_(2) & = & 283\\\\T_(2) & = &(283)/(0.294)\\\\ & = &\textbf{962 K}\\\end{array}\\\text{The final temperature of the carbon dioxide is }\boxed{\textbf{962 K}}](https://img.qammunity.org/2020/formulas/chemistry/middle-school/bwjurrsv6xxnknug7e63o5mclqfxlq591s.png)