Question

Percent Composition Calculations

The Mole
What is the percent of Hin
NH3?
(H = 1.008 amu, N = 14.01 amu)
[?]%

Answer 1

`\boxed{\text{17.76 \% by mass}}`

Step-by-step explanation:

`\text{The mass of one molecule of NH$_(3)$ is:}\\\text{14.01 u N + 3.024 u H = 17.034 u}\\\\\text{mass $\%$ H} =(3.024)/(17.034) * 100 \%} =\textbf{17.76 \%}\\\\\text{Ammonia contains }\boxed{\textbf{17.76 \% H by mass}}`