169k views
5 votes
Solve 2x-3/5=x+6 ASAP

2 Answers

3 votes

Answer:

Problem 1:
(2x-3)/(5)=x+6 gives x=-11

Problem 2:
2x-(3)/(5)=x+6 gives x=33/5

Explanation:

I will do it both ways:

Problem 1:


(2x-3)/(5)=x+6

I don't like the fraction so I'm going to clear by multiplying both sides by 5:


2x-3=5(x+6)

Distribute:


2x-3=5x+30

Subtract 2x on both sides:


-3=3x+30

Subtract 30 on both sides:


-33=3x

Divide both sides by 3:


-11=x

Problem 2:


2x-(3)/(5)=x+6

Clear the fraction by multiplying both sides by 5:


5(2x-(3)/(5))=5(x+6)

Distribute:


10x-3=5x+30

Subtract 5x on both sides:


5x-3=30

Add 3 on both sides:


5x=33

Divide both sides by 5:


x=(33)/(5)

User Adrian Bobrowski
by
6.5k points
5 votes

For this case we must solve the following equation:


\frac {2x-3} {5} = x + 6

Multiplying by 5 on both sides we have:


2x-3 = 5 (x + 6)\\2x-3 = 5x + 30

We add 3 to both sides of the equation:


2x = 5x + 30 + 3\\2x = 5x + 33

Subtracting 5x on both sides:


2x-5x = 33\\-3x = 33

Dividing between -3 on both sides:


x = \frac {33} {- 3}\\x = -11

Answer:

-11

User Joeann
by
7.3k points
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