Question

Find p, if (-3,p) is a point which lies on the graph of equation x-2y=3

Answer 1

Explanation:

x - 2y = 3

let's transform this into a regular function definition

y = ...

so,

x - 2y = 3

x = 2y + 3

x - 3 = 2y

(x - 3)/2 = y

or

y = (x - 3)/2

now, that we have the function definition, we can simply put the given x value of the point into all places, where x is mentored in the expression, and calculate the y value :

y = (-3 - 3)/2 = -6/2 = -3

so, p = -3, and the point on the line is

(-3, -3)