Question

Write an equation of the circle with center (6, 2) and radius 4.

Answer 1

`(x-6)^2+(y-2)^2=16`.

Explanation:

`(x-h)^2+(y-k)^2=r^2` is the equation for a circle with center (h,k) and radius r.

You are given center (6,2) and radius 4.

So we will replace h with 6 and k with 2 and r with 4.

This gives us:

`(x-6)^2+(y-2)^2=4^2`

Simplify:

`(x-6)^2+(y-2)^2=16`.

Answer 2

For this case we have that by definition, the equation of a circle is given by:

`(x-h) ^ 2 + (y-k) ^ 2 = r ^ 2`

Where:

`(h, k):`It is the center of the circle

r: It is the radius of the circle

According to the data we have to:

`(h, k) :( 6.2)\\r = 4`

Substituting:

`(x-6) ^ 2 + (y-2) ^ 2 = 4 ^ 2\\(x-6) ^ 2 + (y-2) ^ 2 = 16`

ANswer:

`(x-6) ^ 2 + (y-2) ^ 2 = 16`