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Write an equation of the circle with center (6, 2) and radius 4.

User FreddieH
by
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2 Answers

4 votes

Answer:


(x-6)^2+(y-2)^2=16.

Explanation:


(x-h)^2+(y-k)^2=r^2 is the equation for a circle with center (h,k) and radius r.

You are given center (6,2) and radius 4.

So we will replace h with 6 and k with 2 and r with 4.

This gives us:


(x-6)^2+(y-2)^2=4^2

Simplify:


(x-6)^2+(y-2)^2=16.

User Srlm
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7.1k points
5 votes

For this case we have that by definition, the equation of a circle is given by:


(x-h) ^ 2 + (y-k) ^ 2 = r ^ 2

Where:


(h, k):It is the center of the circle

r: It is the radius of the circle

According to the data we have to:


(h, k) :( 6.2)\\r = 4

Substituting:


(x-6) ^ 2 + (y-2) ^ 2 = 4 ^ 2\\(x-6) ^ 2 + (y-2) ^ 2 = 16

ANswer:


(x-6) ^ 2 + (y-2) ^ 2 = 16

User Patrice Gagnon
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7.6k points