Question

A machine gun fires 33 g bullets at a speed of 342 m/s. The gun fires 115 bullets/min.What is the average force the shooter must exert to keep the gun from moving?

Answer 1

The average force that the shooter must exert to prevent the weapon from moving is 21.7 Newtons.

Step-by-step explanation:

m=33g=0,033kg

V= 342 m/seg

115 bullets/min= 1 bullet every 0.52 seconds.

By the principle of momentum and amount of movement we have to:

F*t=m*V

F= (m*V)/t

F= (0.033kg * 342 m/s) / 0.52 sec

F= 21.7 Newtons