Question

Graph the equation below

Answer 1

See picture.

In the picture I graphed (0,1) and then graphed (1,3).

I connected the points with a straight-edge.

Explanation:

This question is asking us to use slope-intercept form of a line to answer it.

Slope-intercept form is y=mx+b where m is the slope and b is the y-intercept.

Your equation is y=2x+1 so our m=2 and b=1.

So our y-intercept is 1. This is the first point we graph.

The slope is 2 or as a fraction 2/1. Recall that slope=rise/run. So this tells us after we plot (0,1) we need to go up 2 units and right 1 unit to get one more point to graph. This point will be (0+1,1+2) or just (1,3).

I will draw a graph also to show you this:

Answer 2

Graph Attached Below

Explanation:

Hello!

To graph a line, we just need any two points that belong to that line.

We know the y-intercept, (0,1), given in the equation itself. We can plot that point as our first point.

The second point can be found by using the slope. The slope is 2/1, and we can go up 2 units and to the right 1 unit to find the second point.

The second point is (1,3).