Question

During the time a compact disc (CD) accelerates from rest to a constant rotational speed of 477 rev/min, it rotates through an angular displacement of 0.250 rev. What is the angular acceleration of the CD

Answer 1

`\alpha = 455058\,(rev)/(min^(2))`

Step-by-step explanation:

Let consider that CD accelerates at constant rate. Then, angular acceleration experimented by the CD is:

`\alpha = ((477\,(rev)/(min) )^(2))/(2\cdot (0.250\,rev))`

`\alpha = 455058\,(rev)/(min^(2))`