Question

Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 2.87 × 10-7 m. Find the area of such a sheet that can be formed from 1.00 kg of silver. [silver density = 10500 kg/m3]

Answer 1

A=331.84 m2

Explanation:

Hello

The density of a object is defined by

`d=(m)/(v)`

d is the density

m is the mass of the object

v es the volume of the object

We have

`thickness= t =2.87 * 10^(-7) m\\\ A=unknown=area\\ Volume=Area*thickness\\m=1 kg \\\\\\d=10500kg/m^(3)`

`d=(m)/(v)\\ v=(m)/(d)\\ A*t=(m)/(d)\\ A=(m)/(d*t)\\ \\A=(1 kg)/(10500(kg)/(m^(3) )*2.87*10^(-7)m)\\A=331.84m^(2)`

I hope it helps