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Consider the function f(x)=|x+3|−5 and its graph, which follows.

An absolute value function with vertex (negative 3, negative 5). It passes through (negative 8, 0) & (2, 0).


Suppose the function is transformed by the function g(x) = −1/5f(x).

Please graph response

2 Answers

4 votes

Answer:

n

Explanation:

User Nrussell
by
6.8k points
4 votes

Answer:

The graph in the attached figure

Explanation:

we have


f\left(x\right)=\left|x+3\right|-5

Obtain the function g(x)


g(x)=-(1)/(5) f(x)

substitute


g(x)=-(1)/(5) [\left|x+3\right|-5]


g(x)=-(1)/(5)\left|x+3\right|+1

using a graphing tool

The graph in the attached figure

The vertex is the point (-3,1)

The x-intercepts are the points (-8,0) and (2,0)

The y-intercept is the point (0,0.4)

Consider the function f(x)=|x+3|−5 and its graph, which follows. An absolute value-example-1
User KayakDave
by
7.7k points