Question

A bag contains 18 balls to green five black eight blue one brown one red and one white if 17 balls of a move from the bag at random what is the probability that a brown ball has been removed

Answer 1

`P(Brown) = 0.0556` or
`P(Brown) = (1)/(18)`

Explanation:

Given

`Total = 18`

`Green = 2`

`Black = 5`

`Blue = 8`

`Brown = 1`

`Red = 1`

`White = 1`

Required

Determine the probability of selecting a brown ball

This is calculated as thus:

`P(Brown) = (Brown)/(Total)`

Substitute values for Brown and Total

`P(Brown) = (1)/(18)`

The answer can be in fraction or solved further as;

`P(Brown) = 0.0556`