Question

lectric device, which heats water by immersing a resistance wire in the water, generates 50 cal of heat per second when an electric potential difference of 12 V is placed across its leads. What is the resistance of the heater wire?

Answer 1

The resistance of the heater wire is of R= 0.68 Ω.

Step-by-step explanation:

1 cal/s = 4.184 W

P= 50 cal/s = 209.2 W

V= 12V

P= V* I

I= P/V

I= 17.43 A

P= I² * R

R= P / I²

R= 0.68 Ω