Answer:
The correct gene order is H-e-B
Recombination frequency between genes E and B = 10%
Step-by-step explanation:
In linkage parental genotype is always in greater number than recombinants, hence:
400 = eeHhBb : Parental
426 = Eehhbb : Parental
Double crossovers have the smallest number hence:
EeHhBb = 4 : Double recombinant
eehhbb = 2 : Double recombinant
Double cross over places middle allele from one sister chromatid to other one. Hence a non parental allele of the middle gene is present with parental alleles of the flanking genes.
Here recombinant type is EHB and parental type is eHB . Only gene order H-e-B would result in double cross over which would give EHB and ehb double recombinants. Hence, the correct gene order is H-e-B.
Single crossover between gene E and B would result in Heb and hEB progeny ( 48 and 46 )
Recombination frequency between E and B = [(Double recombinants + Single E and B recombinants) / Total progeny)*100]
= [ (4 + 2 + 48 + 46)/1000] * 100
= 100/1000
= 0.1 * 100 = 10%