2 Answers

Rickless · Answer 1 · 2021-01-02T02:57:23+0000

Answer:

$h(x)=+-\sqrt{(x+4)/(9) }$

Explanation:

Hello

I think I can help you with this

Let

$y = 9x^(2)-4\\h(x)=y^(-1)$

to find the inverse of y(
y^(-1) )

Step 1

switch x and y

$y = 9x^(2)-4\\\\x= 9y^(2)-4$

Step 2

Now solve the equation for y (isolating y)

$x= 9y^(2)-4\\Add\ 4\ to\ both\ sides\\x+4= 9y^(2)-4+4\\x+4=9y^(2)\\divide\ each\ side\ by\ 9\\(x+4)/(9) =(9y^(2))/(9)\\\\x+4=y^(2) \\$

$h(x)=+-\sqrt{(x+4)/(9) }$

Have a great day

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