Final answer:
Approximately 9.32 liters of radon gas would be in 3.43 moles at standard temperature and pressure (273K and 100 kPa).
Step-by-step explanation:
To find the number of liters of radon gas in 3.43 moles at standard temperature and pressure (STP), we can use the ideal gas law equation: PV = nRT.
Substituting the given values into the equation:
Pressure (P) = 100 kPa
Temperature (T) = 273 K
Number of moles (n) = 3.43 mol
Ideal gas constant (R) = 8.31 L·kPa/mol·K
Volume (V) is what we need to find.
Using the equation PV = nRT, we can rearrange it to solve for the volume:
V = (nRT) / P
Plugging in the values:
V = (3.43 mol)(8.31 L·kPa/mol·K)(273 K) / 100 kPa
V ≈ 9.32 L
Therefore, there would be approximately 9.32 liters of radon gas in 3.43 moles at standard temperature and pressure.