Question

A soft drink contains 11.5% sucrose (C12H22O11) by mass. How much sucrose, in grams, is contained in 355 mL (12 oz) of the soft drink? (Assume a density of 1.04 g/mL.)

Express your answer to three significant figures and include appropriate units.

Answer 1

42.5 g

Step-by-step explanation:

Calculate the mass of the soft drink given the density and volume:

355 mL × 1.04 g/mL = 369.2 g

Now calculate the mass of sucrose given the percentage:

0.115 × 369.2 g = 42.46 g

Rounded to 3 significant figures, the mass is 42.5 g.

Answer 2

42.458 g of sucrose is contained in 355 mL (12 oz) of the soft drink

Step-by-step explanation:

Volume of the soft drink = 355mL

Density = 1.04 g/mL

We know

Density = Mass / Volume

Rearranging the formula

Mass of soft drink = Density × volume

`=1.04 g/mL * 355mL=369.2 g`

`Mass = \frac {(mass of solute)}{(mass of solution )} * 100%`

`11.5  = \frac {(mass of solute (sucrose))}{(mass of solution(soft drink) )} * 100%`

`11.5  = \frac {(mass of solute (sucrose))}{(369.2 g)} * 100%`

So

Mass of sucrose

`=\frac {(11.5 * 369.2g)}{(100)}`

= 42.458 g is the Answer