Question

Solve 16t2 - 96t + 48 = 0.

Answer 1

the question is not written correctly 16t2 can't be used in the equation

Explanation:

do it it correctly you need to combine the like numbers, subtract the 48 from both sides and then divide the number with the t to both sides.

Answer 2

We get the value of t as:

`t=3+√(6)\ and\ t=3-√(6)`

Explanation:

We are asked to solve the given equation for t.

The quadratic equation in terms of the variable t is given by:

`16t^2-96t+48=0`

On dividing both side of the equation by 16 we get:

`t^2-6t+3=0`

Now, we know that any quadratic equation of the type:

`at^2+bt+c=0` has solution as :

`t=(-b\pm √(b^2-4ac))/(2a)`

Here,

`a=1,\ b=-6\ and\ c=3`

i.e.

`t=(-(-6)\pm √((-6)^2-4* 1* 3))/(2* 1)\\\\t=(6\pm √(36-12))/(2)\\\\t=(6\pm √(24))/(2)\\\\t=(6\pm 2√(6))/(2)\\\\t=3\pm √(6)`

i.e.

`t=3+√(6)\ and\ t=3-√(6)`