Answer:
0.193 M to the nearest thousandth.
Step-by-step explanation:
Molar mass of copper (ii) chloride
= 63.546 + 2* 35.45
= 134.446 g.
So in 2.60L of 1 M solution there is 134.446 * 2.6
= 349.56 g of copper chloride.
So the molarity of our solution is 67.3 / 349.56
= 0.193 M.