Question

(-b3+ 3b2 + 8) - (? - 5b2 - 9) = 5b3 + 8b2 + 17
? =
DONE

Answer 1

Answer with Step-by-step explanation:

Let ?=x

We have to find the value of x in:

`(-b^3+3b^2+8)-(x-5b^2-9)=5b^3+8b^2+17`

Adding
`b^3` on both sides, we get

`-b^3+3b^2+8-x+5b^2+9+b^3=5b^3+8b^2+17+b^3`

`3b^2+8-x+5b^2+9=5b^3+8b^2+17+b^3`

Combining the like terms on both side, we get

`8b^2+17-x=6b^3+8b^2+17`

Subtracting both sides by 8b², we get

`8b^2-x+17-8b^2=6b^3+8b^2+17-8b^2`

`-x+17=6b^3+17`

subtracting both sides by 17, we get

`-x+17-17=6b^3+17-17`

`-x=6b^3`

Dividing both sides by -1, we get

`x=-6b^3`

Hence, ? =
`-6b^3`