Answer:
=67.65 grams of sodium chloride.
Step-by-step explanation:
In this explanation, we shall assume that the limiting reagent was NaOH only and the amount of HCl used was sufficient.
NaOH + HCl → NaCl + H₂O
In the equation, the ratio of NaOH used to the NaCl produced will be 1:1
The number of moles of NaOH in 46.3 g.
Number of moles = mass/RMM
=46.3g/40g/mol
=1.1575 moles.
Since the reaction ratio is 1:1, the Number of moles of NaCl produced is also 1.1575 moles.
The mass of 1.1575 moles of NaCl is: 1.1575 moles × 58.443g/mol
=67.65 grams of sodium chloride.