Answer:
x = 3, y = 4 and z = -5.
Explanation:
Use the elimination method:
-3x + 2y + z = -6...........(1)
x + 3y + 2z = 5..............(2)
4x + 4y + 3z = 13..........(3)
Multiply the first equation by -2:
6x - 4y - 2z = 12 Add this to equation (2):
7x - y = 17...........(4)
Now Multiply equation (2) by 3 and equation (3) by -2
3x + 9y + 6z = 15 ............(5)
-8x - 8y - 6z = -26............(6) Adding (5) + (6):
-5x + y = -11..........(7)
Now Add (7) and (4):
2x = 6
x = 3.
Now substitute for x in (4):
7(3) - y = 17
-y = 17 - 21 = -4
y = 4.
Finally substitute for x and y in equation (3) to find z:
4(3) + 4(4) +3z = 13
3z = 13 - 12 - 16 = -15
z = -5.