Question

Step by step to how to solve quadratic equation given the roots ​

Answer 1

`\displaystyle\it\\\text{We have the equation: }\\\\ax^2+bx+c=0\\\\\text{We find the roots:}\\\\x_(12)=(-b\pm√(b^2-4ac))/(2a)\\\\x_(1)=(-b+√(b^2-4ac))/(2a)\\\\x_(2)=(-b-√(b^2-4ac))/(2a)\\\\\text{If } b^2-4ac>0 \text{ then }x_1, x_2\in~R\\\\\text{If } b^2-4ac=0 \text{ then }x_1=x_2\in~R\\\\\text{If } b^2-4ac<0 \text{ then }x_1, x_2\in~C`

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