Question

You heat a circular steel sheet of diameter 50.0 cm in an oven. What will be the radius for 50 K increase in temperature?

Answer 1

R = 50.016 cm

Step-by-step explanation:

Coefficient of thermal expansion for steel is given as

`\alpha = 13 * 10^(-6) per ^0C`

now as we know that the change in the length due to thermal expansion depends of change in temperature and initial length of the object

so here we will have

`\Delta R = R_o \alpha \Delta T`

here we know that

`R_o = (50)/(2) cm = 25 cm`

`\Delta T = 50 K`

now we will have

`\Delta R = (25)(13 * 10^(-6))(50)`

`\Delta R = 0.016 cm`

so final radius of the disc will be R = 50.016 cm