Answer:
D
Step-by-step explanation:
The general equation for this is
F = G*m1*m2/r^2
If the distance (r) remains the same and m1 and m2 are both doubled, then the equation becomes
F1 = G * (2m1)(2m2)/r^2
F1 = 4 [G * m1 * m2)/r^2 ]
So F1 is 4 times as large as the initial Force (F)
Answer: D